document.write( "Question 415954: how do you find the complex zeros of f(x)=x^3-8x^2+25x-26? \n" ); document.write( "
Algebra.Com's Answer #291553 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! f(x)=x^3-8x^2+25x-26\r \n" ); document.write( "\n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "The best way to find all the roots of functions higher than second degree is to start by displaying this function on a graphing calculator to see if there are any real roots. As you can see from the graph below,the given cubic function has only one real root=2. \n" ); document.write( ".. \n" ); document.write( "Next, divide the function by (x+2),by long division or use synthetic division:\r \n" ); document.write( "\n" ); document.write( "When you do this, you will get a quotient=x^2-6x+13 \n" ); document.write( "Solving this second degree equation using the quadratic formula: \n" ); document.write( "a=1, b=-6, c=13\r \n" ); document.write( "\n" ); document.write( "x=-(-6)+-sqrt((-6)^2-4*1*13)/2*1 \n" ); document.write( " =(6+-sqrt(36-52)/2 \n" ); document.write( " =(6+-sqrt(-16))/2 \n" ); document.write( " =(6+-4i)/2 \n" ); document.write( " =3+-2i\r \n" ); document.write( "\n" ); document.write( "Ans: \n" ); document.write( "one real root, 2 \n" ); document.write( "two complex roots,3+2i and 3-2i \n" ); document.write( "See the graph below: \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |