document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44207>Question 44207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
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document.write( "A motorcycle daredevil is planning a stunt to perform at a county fair. A ramp must be built to give him a 20% grade, or slope. If the vertical height at the end of the ramp must be 11 ft to assure that the stunt is a success, what must be the length of the horizontal run?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29153 by </B><A HREF=/tutors/aboutme.mpl?userid=adamchapman><B>adamchapman(301)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=adamchapman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29153\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 20% grade means the height of the ramp is 20% of the ramps horizontal length.<BR>\n" );
document.write( "Let H=height and L=length of ramp.<BR>\n" );
document.write( "H=0.2L<BR>\n" );
document.write( "rearranging gives:<BR>\n" );
document.write( "L= H/0.2 = 5H<BR>\n" );
document.write( "L= 5 x 11 = 55<BR>\n" );
document.write( "So  the length of the horizontal run must be 55ft.\r<BR>\n" );
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document.write( "I hope this helps.<BR>\n" );
document.write( "P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk<BR>\n" );
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