document.write( "Question 415944: find three consecutive odd intergers such that 4 times the product of the second and third is 12 greater than 20 times the sum of the first and second \n" ); document.write( "
Algebra.Com's Answer #291528 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! find three consecutive odd integers such that 4 times the product of the second and third is 12 greater than 20 times the sum of the first and second \n" ); document.write( "--------- \n" ); document.write( "1st: 2x-1 \n" ); document.write( "2nd: 2x+1 \n" ); document.write( "3rd: 2x+3 \n" ); document.write( "------------- \n" ); document.write( "Equation: \n" ); document.write( "4[(2x+1)(2x+3)] = 20[4x] \n" ); document.write( "---- \n" ); document.write( "4[4X^2+8x+3] = 80x \n" ); document.write( "---- \n" ); document.write( "4x^2+8x+3 = 20x \n" ); document.write( "--- \n" ); document.write( "4x^2-12x+3 = 0 \n" ); document.write( "--- \n" ); document.write( "x = [12 +- sqrt(144 - 4*4*3)]/8 \n" ); document.write( "--- \n" ); document.write( "x = [12 +- sqrt(96)]/8 \n" ); document.write( "--- \n" ); document.write( "x = [12 +- 4sqrt(6)]/8 \n" ); document.write( "---- \n" ); document.write( "x = (3/2) +- sqrt(6) \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============ \n" ); document.write( " |