document.write( "Question 415948: This is the only inverse-related section, so, here goes:\r
\n" ); document.write( "\n" ); document.write( "Find the inverse function of Y = (exp)3(sqrt)2x+1\r
\n" ); document.write( "\n" ); document.write( "I get that you turn f(x) into Y, and replace the X with Y, and vice versa; then move the (exp)3 onto the Y to get rid of the square root. So, it then becomes:\r
\n" ); document.write( "\n" ); document.write( "X^3 = 2Y+1\r
\n" ); document.write( "\n" ); document.write( "After that, I'm lost. If I subtract the 1, it becomes X^3-1 = 2Y, but, I can't divide by 2 because there needs to be an X in the denominator.
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Algebra.Com's Answer #291513 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=root%283%2C2x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=root%283%2C2x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=root%283%2C2y%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3=2y%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3-1=2y\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E3-1%29%2F2=y\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28x%5E3-1%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "So the inverse function is \r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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