document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=415948>Question 415948</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is the only inverse-related section, so, here goes:\r<BR>\n" );
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document.write( "Find the inverse function of Y = (exp)3(sqrt)2x+1\r<BR>\n" );
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document.write( "I get that you turn f(x) into Y, and replace the X with Y, and vice versa; then move the (exp)3 onto the Y to get rid of the square root. So, it then becomes:\r<BR>\n" );
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document.write( "X^3 = 2Y+1\r<BR>\n" );
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document.write( "After that, I'm lost. If I subtract the 1, it becomes X^3-1 = 2Y, but, I can't divide by 2 because there needs to be an X in the denominator. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #291512 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=291512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = cbrt(2x+1)<BR>\n" );
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document.write( "1st: Interchange to get:<BR>\n" );
document.write( "x = cbrt(2y+1)<BR>\n" );
document.write( "cube both sides:<BR>\n" );
document.write( "x^3 = 2y+1<BR>\n" );
document.write( "---<BR>\n" );
document.write( "2y+1 = x^3<BR>\n" );
document.write( "2y = x^3 -1<BR>\n" );
document.write( "y = (x^3-1)/2<BR>\n" );
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document.write( "That is the inverse.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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