document.write( "Question 415873: The length of a rectangle is 5 inches more than the width. The perimeter is 30 inches. Find the length and width.
\n" ); document.write( "L =... inches
\n" ); document.write( "w= ... inches\r
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Algebra.Com's Answer #291479 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

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\n" ); document.write( "Let x and (x+5in) represent the width and length respectively
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\n" ); document.write( " 2(x+5in) + 2x = 30in
\n" ); document.write( "Solving for x
\n" ); document.write( " 4x = 20
\n" ); document.write( " x = 5in, the width. The length is 10in (5in + 5in)
\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 2*10in + 2*5in = 20in + 10in = 30in
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