document.write( "Question 415790: Please help me solve this question. I don't know what operation to do:
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document.write( " If x^y = 16, where x and y are positive integers and x is less than y, what is the value of x-y ? \n" );
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Algebra.Com's Answer #291426 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! If \n" ); document.write( "16^1 = 16, but the problem states that x < y. \n" ); document.write( "4^2 = 16, but again x < y. \n" ); document.write( "So the only possibility is 2^4 = 16, so x=2, y=4 -> x-y = 2-4 = -2. \n" ); document.write( " |