document.write( "Question 415742: Sam leaves on a long trip driving at a steady rate of 45mph. Allen leaves from the same location traveling the same distance 2 hours later. He drives at a steady rate of 55mph. How long after Allen leaves home will he catch up to Sam? \n" ); document.write( "

Algebra.Com's Answer #291411 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Let x and ( x-2hr) represent the times that Sam and Allen traveled respectively
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document.write( " Question states***  D = r*t  (distances being the same for both
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document.write( " 45mph*x = 55mph(x-2)
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document.write( "Solving for x
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document.write( "    110 = 10x
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document.write( "     11hr = x, time Sam traveled.  Allen traveled 9 hrs.\r
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document.write( "CHECKING our Answer***
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document.write( "45mph*11hr = 55mph*9hr = 495mi \n" );
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