document.write( "Question 415705: how do i solve y=-x \r
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document.write( "also how do i solve x=3y? \n" );
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Algebra.Com's Answer #291380 by Theo(13342)![]() ![]() You can put this solution on YOUR website! your equation is y = -x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your dependent variable is y and your independent value is -x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you pick values of x and then you find values of y that correspond to that.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 1, y = -1 \n" ); document.write( "when x = 2, y = -2 \n" ); document.write( "when x = 3, y = -3 \n" ); document.write( "when x = 0, y = 0 \n" ); document.write( "when x = -1, y = 1 \n" ); document.write( "when x = -2, y = 2 \n" ); document.write( "etc.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation is now x = 3y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your dependent variable is now x and your independent variable is now y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you would select values of y and then you would solve for values of x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when y = 1, x = 3*1 = 3 \n" ); document.write( "when y = 2, x = 3*2 = 6 \n" ); document.write( "when y = -5, x = 3*(-5) = -15 \n" ); document.write( "etc.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "with the equation x = 3y, if you want to make x the independent variable and you want to make y the dependent variable, you would need to switch the equation around.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you would do that as follows:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 3*y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of the equation by 3 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x/3 = y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "flip the sides of the equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = x/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have now made x the independent variable and y the dependent variable.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 3, y = 3/3 = 1 \n" ); document.write( "when x = 6, y = 6/3 = 2 \n" ); document.write( "when x = -15, y = -15/3 = -5\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |