document.write( "Question 415647: An airplane travels 400km at a certain speed. One year later, the same airplane does the same trip at a speed 50km/hr faster than a year ago, and it takes one hour less time. What was the speed of the airplane one year ago \n" ); document.write( "
Algebra.Com's Answer #291349 by mananth(16946)![]() ![]() You can put this solution on YOUR website! speed x \n" ); document.write( "speed x+50 after one year \n" ); document.write( " \n" ); document.write( "Distance = same 400km \n" ); document.write( "original time – time with increased speed =1hour \n" ); document.write( "t=d/t \n" ); document.write( "400/x-400/(x+400 )=1 \n" ); document.write( "LCD= (x+ 400) \n" ); document.write( "multiply by LCD \n" ); document.write( "400(x+400)-400x =x(x+400 ) \n" ); document.write( "400x+160000-400x =1X^2+400x \n" ); document.write( "160000=X^2+400x \n" ); document.write( "X^2+400x-160000 =0 \n" ); document.write( "solve using quadratic formula\r \n" ); document.write( "\n" ); document.write( "a= 1 , b = 400 , c ==-160000 .\r \n" ); document.write( "\n" ); document.write( "b^2-4ac=800000\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "x1= 247.21 \n" ); document.write( "x2 is negative so ignore \n" ); document.write( "original speed = 247.21 mph \n" ); document.write( "after one year speed= 297.21 mph\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |