document.write( "Question 414488: solve the following inequalities.
\n" ); document.write( "12<6x^2+x \n" ); document.write( "
Algebra.Com's Answer #291347 by lwsshak3(11628)\"\" \"About 
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solve the following inequalities.
\n" ); document.write( "12<6x^2+x\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "6x^2+x>12
\n" ); document.write( "First step is to set inequality=to zero, than solve for zeros of the quadratic equation.\r
\n" ); document.write( "\n" ); document.write( "6x^2+x-12=0
\n" ); document.write( "solve using following quadratic equation: with a=6,b=1.c=-12
\n" ); document.write( "..
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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\n" ); document.write( "\n" ); document.write( "x=(-1+-sqrt(1-4*6*-12)/2*6
\n" ); document.write( " =(-1+-sqrt(289))/12
\n" ); document.write( " =(-1+-17)/12=-18/12,16/12
\n" ); document.write( "x=-3/2
\n" ); document.write( "x=4/3
\n" ); document.write( "in factored form:
\n" ); document.write( "(x+3/2)(x-4/3)>0
\n" ); document.write( "Show these points,-3/2 and 4/3 on a number line.
\n" ); document.write( "By using test points you see that for x>4/3 the function is positive.
\n" ); document.write( "Similarly, you will see that for x<-3/2, the function is also positive
\n" ); document.write( "For -3/2 < x < 4/3, the function, however is negative which does not satisfy the inequality.
\n" ); document.write( "The solution therefore as expressed in interval notation:
\n" ); document.write( "(-infinity,-3/2) U (4/3, infinity)\r
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