document.write( "Question 415595: what is the focal length of
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document.write( " (x − 4) ^2 /36 + (y + 5) ^2/ 25 = 1
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Algebra.Com's Answer #291346 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! what is the focal length of \n" ); document.write( "(x − 4) ^2 /36 + (y + 5) ^2/ 25 = 1 \r \n" ); document.write( "\n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "(x−4)^2/36+(y+5)^2/25=1 \n" ); document.write( "This is an ellipse with centers at (4,-5) with horizontal major axis. \n" ); document.write( "Standard form for this ellipse: (x-h)^2/a^2+(y-k)^2/b^2=1 with center at (h,k) \n" ); document.write( "a^2=36 \n" ); document.write( "b^2=25 \n" ); document.write( "c^2=a^2-b^2 \n" ); document.write( "c=sqrt(36-25)=sqrt(11) \n" ); document.write( "ans: \n" ); document.write( "focal length of ellipse=sqrt(11) \n" ); document.write( " |