document.write( "Question 415609: i have 3 problems to figure out. the first one is: 14-10+x<-x-8. i started to do 4+x<-x-8 then i was lost.
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document.write( "2. 1(1+7)-6(-7-x)<40-4 i got -1-7x+42-6x<40-4 then i did more and got -1+42-13<44, then 41-13x<44 and subtracted 41 from 41 and 44. im not sure if im right but that's how far i got.\r
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document.write( "3. -5(1-5x)+5(-8x-2)>-4x-8x. i haven't got to that one yet because i have been to frustrated with the other 2 problems. \n" );
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Algebra.Com's Answer #291324 by mananth(16946)![]() ![]() You can put this solution on YOUR website! the first one is: 14-10+x<-x-8. \n" ); document.write( "14-10+x<-x-8. \n" ); document.write( "4+x<-x-8 \n" ); document.write( "add -4 \n" ); document.write( "x<-x-8-4 \n" ); document.write( "x<-x-12 \n" ); document.write( "add +x \n" ); document.write( "x+x<-x+x-12 \n" ); document.write( "2x<-12 \n" ); document.write( "/2 \n" ); document.write( "x<-6 \n" ); document.write( "....\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. 1(1+7)-6(-7-x)<40-4 \r \n" ); document.write( "\n" ); document.write( "8+42+6x<36 \n" ); document.write( "50+6x<36 \n" ); document.write( "add -50 \n" ); document.write( "6x<36-50 \n" ); document.write( "6x<-14 \n" ); document.write( "/6 \n" ); document.write( "x<-14/6 \n" ); document.write( "x<-7/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-5(1-5x)+5(-8x-2)>-4x-8x \n" ); document.write( "-5+25x-40x-10>-4x-8x \n" ); document.write( "-15-15x>-12x \n" ); document.write( "add 12x \n" ); document.write( "-15>-12x+15x \n" ); document.write( "-15>3x \n" ); document.write( "/3 \n" ); document.write( "-5>x \n" ); document.write( " \n" ); document.write( " |