document.write( "Question 415474: I am having trouble making the relationships of pii or 3.14..... for instance i know that piiR^2 (pie x radius squared) is how you find the area of a circle
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document.write( "I know also you can use pii x D^2 divided by 4 because r^2 = (D/2)^2 = (d^2)/4
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document.write( "recently i was given the formula for volume of a pipe .785 x diameter x length where .785 is pi/4 could you please explain how you simplify the formula to get .785 x diameter x length for volume of a pipe i understand .785 is 1/4 pii but i dont understand how you get from piiR^2 x length to .785 X dia. x length for the volume and ive worked both ways the only one close is .785 formula \n" );
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Algebra.Com's Answer #291270 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! recently i was given the formula for volume of a pipe .785 x diameter x length where .785 is pi/4 could you please explain how you simplify the formula to get .785 x diameter x length for volume of a pipe i understand .785 is 1/4 pii but i dont understand how you get from piiR^2 x length to .785 X dia. x length for the volume and ive worked both ways the only one close is .785 formula \n" ); document.write( "------- \n" ); document.write( "Volume = Area of a cross section *length \n" ); document.write( "--- \n" ); document.write( "But Surface = Circumference * length \n" ); document.write( "S = pi*D*L \n" ); document.write( "------ \n" ); document.write( "0.785*diameter*length looks like a surface formula to me. \n" ); document.write( "----- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "======== \n" ); document.write( " |