document.write( "Question 415469: How would you do a linear system that has one equation with a fraction, using the elimination method? Such as the following: 3/2x + y= -5/2
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document.write( " 4x + y= -5?
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document.write( "Your help is much appreciated. \n" );
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Algebra.Com's Answer #291267 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! When you have an equation you NEVER have to \n" ); document.write( "deal with fractions. \n" ); document.write( "----- \n" ); document.write( "3/2x + y= -5/2 \n" ); document.write( "4x + y= -5 \n" ); document.write( "--------- \n" ); document.write( "Multiply thru by 2 to get: \n" ); document.write( "3x + 2y = -5 \n" ); document.write( "4x + y = -5 \n" ); document.write( "---- \n" ); document.write( "Multiply thru the 2nd Eq. by 2: \n" ); document.write( "3x + 2y = -5 \n" ); document.write( "8x + 2y = -10 \n" ); document.write( "--- \n" ); document.write( "Subtract and solve for \"x\": \n" ); document.write( "5x = -5 \n" ); document.write( "x = -1 \n" ); document.write( "---- \n" ); document.write( "Solve for \"y\": \n" ); document.write( "4x+y = -5 \n" ); document.write( "4(-1) + y = -5 \n" ); document.write( "-4 + y = -5 \n" ); document.write( "y = -1 \n" ); document.write( "---- \n" ); document.write( "Solution: (-1,-1) \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========== \n" ); document.write( " \n" ); document.write( " |