document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=415343>Question 415343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The lenght of a rectangle is one less than twice the width. If its perimeter is 34\", what are the dimensions ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #291199 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=291199\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1) 2l + 2w = 34, where l = length, w = width<BR>\n" );
document.write( "(2) 2w - 1 = l, which states that the length is ONE less than TWICE the width<BR>\n" );
document.write( "From (2), 2w = l + 1<BR>\n" );
document.write( "Substituting into (1) gives 2l + l + 1 = 34, or 3l + 1 = 34<BR>\n" );
document.write( "Solving for l gives l = 11.<BR>\n" );
document.write( "Using (2), 2w - 1 = 11, or w = 12/2 = 6.<BR>\n" );
document.write( "Answers: length = 11, width = 6 </SPAN>\n" );
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