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document.write( "Hi
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document.write( "Using the vertex form of a parabola,
where(h,k) is the vertex
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document.write( "x^2+5+2x = 0
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document.write( "y = x^2+ 2x + 5 |completing Square to put into vertex form for graphing purposes
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document.write( " y = (x+1)^2 - 1 + 5
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document.write( " y = (x+1)^2 + 4 |Vertex is (-1,4) and line of symmetry is x = -1 and(0,5) the y-intercept
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document.write( "NO real solutions, Parabola does not cross the x-axis.
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document.write( "0 = (x+1)^2 + 4
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document.write( " -1 ± 2i = x
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