document.write( "Question 415258: Solve x^2+5=-2x by graphing \n" ); document.write( "
Algebra.Com's Answer #291174 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi
\n" ); document.write( "Using the vertex form of a parabola, \"y=a%28x-h%29%5E2+%2Bk\" where(h,k) is the vertex
\n" ); document.write( "x^2+5+2x = 0
\n" ); document.write( "y = x^2+ 2x + 5 |completing Square to put into vertex form for graphing purposes
\n" ); document.write( " y = (x+1)^2 - 1 + 5
\n" ); document.write( " y = (x+1)^2 + 4 |Vertex is (-1,4) and line of symmetry is x = -1 and(0,5) the y-intercept
\n" ); document.write( "NO real solutions, Parabola does not cross the x-axis.
\n" ); document.write( "0 = (x+1)^2 + 4
\n" ); document.write( " -1 ± 2i = x
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