document.write( "Question 415215: A woman can hike 1 mph faster down a trail then she can uphill.
\n" ); document.write( "It takes her 3 hours to go downhill and 6 hours uphill.
\n" ); document.write( "What is her speed downhill? \n" ); document.write( "

Algebra.Com's Answer #291130 by josmiceli(19441) $\"\"$ $\"About$

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Going downhill:
\n" ); document.write( " $\"d+=+%28r+%2B+1%29%2A3\"$
\n" ); document.write( "Going uphill:
\n" ); document.write( " $\"d+=+r%2A6\"$
\n" ); document.write( "(I'm assuming the uphill and
\n" ); document.write( "downhill trips are the same distance)
\n" ); document.write( " $\"%28r+%2B+1%29%2A3+=+6r\"$
\n" ); document.write( " $\"3r+%2B+3+=+6r\"$
\n" ); document.write( " $\"3r+=+3\"$
\n" ); document.write( " $\"r+=+1\"$
\n" ); document.write( " $\"r+%2B+1+=+2\"$
\n" ); document.write( "Her speed downhill is 2 mi/hr
\n" ); document.write( "check answer:
\n" ); document.write( " $\"d+=+%28r+%2B+1%29%2A3\"$
\n" ); document.write( " $\"d+=+2%2A3\"$
\n" ); document.write( " $\"d+=+6\"$ mi
\n" ); document.write( "and
\n" ); document.write( " $\"d+=+r%2A6\"$
\n" ); document.write( " $\"d+=+1%2A6\"$
\n" ); document.write( " $\"d+=+6\"$ mi
\n" ); document.write( "OK \n" ); document.write( "

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