document.write( "Question 415151: The probability that a player makes a free throw is 0.60. In 3 free throws, find the probability that the player makes
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Algebra.Com's Answer #291096 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "The probability that a player makes a free throw is 0.60. In 3 free throws, find the probability that the player makes:
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document.write( "Note: The probability of x successes in n trials is: 
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document.write( "P = nCx*  where p and q are the probabilities of success and failure respectively. 
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document.write( "In this case p = .6 & q =.4
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document.write( "nCx = 
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document.write( "a. exactly 3 free throws = .6^3 = .216
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document.write( "b. at least 1 free throw = 1 - .4^3 = 1 -.064 = .936
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document.write( "c. an odd number of free throws (1 '0r' 3) = 3*.6*.4^2 + .6^3 = .288 +.216
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document.write( "d. if X=number of free throws a player can successfully make. Compute the value of the following:
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document.write( "i. Mean = .6X                      |mean = np
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document.write( "ii. Variance = .6*.4*X = .24X      |variance = npq
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