document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=415136>Question 415136</A>: <I><SPAN STYLE=\"word-break: break-all;\"> why is x=-1 the solution of (x-2)*(3x) + (2x-1)*(x+4) = (5x-1)*(x+1)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #291090 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=291090\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> when you substitute -1 for x, you get the following:\r<BR>\n" );
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document.write( "original equation:\r<BR>\n" );
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document.write( "(x-2)*(3x) + (2x-1)*(x+4) = (5x-1)*(x+1)\r<BR>\n" );
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document.write( "when you replace x with -1:\r<BR>\n" );
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document.write( "(x-2)*(3x) becomes -3*-3 which equals 9<BR>\n" );
document.write( "(2x-1)*(x+4) becomes -3*3 which equals -9<BR>\n" );
document.write( "(5x-1)*(x+1) becomes -6*0 which equals 0\r<BR>\n" );
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document.write( "the equation becomes:\r<BR>\n" );
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document.write( "9 - 9 = 0 which becomes 0 = 0 which is true.\r<BR>\n" );
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document.write( "they are equal because when you substitute (-1) for x, the equation becomes 0 = 0 which is true.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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