document.write( "Question 415092: If Alexandra increases her usual driving speed by 15 km/h, it will take her 2h less to make a trip to her grandparents' house. If she decreases her usual speed by 15 km/h, it will take her 3 h more than usual to make the trip. How long is the trip? \n" ); document.write( "
Algebra.Com's Answer #291066 by mananth(16946)![]() ![]() You can put this solution on YOUR website! If Alexandra increases her usual driving speed by 15 km/h, it will take her 2h less to make a trip to her grandparents' house. If she decreases her usual speed by 15 km/h, it will take her 3 h more than usual to make the trip. How long is the trip?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let usual speed = x mph \n" ); document.write( "speed increased by 15km/h \n" ); document.write( "speed = x+15 km/h \n" ); document.write( "... \n" ); document.write( "usual time = y \n" ); document.write( "time with increased speed = y-2\r \n" ); document.write( "\n" ); document.write( "xy = (x+15)(y-2) \n" ); document.write( "xy=xy-2x+15y-30 \n" ); document.write( "2x-15y=-30.....................1\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "speed decreased by 15 km/h \n" ); document.write( "time = y+3 \n" ); document.write( ".. \n" ); document.write( "xy = (x-15)(y+3) \n" ); document.write( "xy=xy+3x-15y-45 \n" ); document.write( "3x+15y=-45....................2\r \n" ); document.write( "\n" ); document.write( "2x-15y=-30.....................1\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "speed decreased by 15 km/h \n" ); document.write( "time = y+3 \n" ); document.write( ".. \n" ); document.write( "xy = (x-15)(y+3) \n" ); document.write( "xy=xy+3x-15y-45 \n" ); document.write( "3x+15y=-45....................2\r \n" ); document.write( "\n" ); document.write( "2x-15y=-30.............1 \n" ); document.write( "-3x+15y =-45 .............2 \n" ); document.write( " \n" ); document.write( "multiply (1)by 1 \n" ); document.write( "Multiply (2) by 1 \n" ); document.write( "2x-15y =-30 \n" ); document.write( "-3x+15y =-45 \n" ); document.write( " \n" ); document.write( "Add the two equations \n" ); document.write( "-1x=-75 \n" ); document.write( "/-1 \n" ); document.write( "x=75 km/h \n" ); document.write( " \n" ); document.write( "plug value of x in (1) 2x-15y =-30 \n" ); document.write( "150-15y =-30 \n" ); document.write( "-15y =-30+-150 \n" ); document.write( "-15y=-180 \n" ); document.write( "y=12 hours\r \n" ); document.write( "\n" ); document.write( "Distance = speed * time \n" ); document.write( "Distance = 75*12= 900 km \n" ); document.write( " \n" ); document.write( " |