document.write( "Question 415092: If Alexandra increases her usual driving speed by 15 km/h, it will take her 2h less to make a trip to her grandparents' house. If she decreases her usual speed by 15 km/h, it will take her 3 h more than usual to make the trip. How long is the trip? \n" ); document.write( "
Algebra.Com's Answer #291066 by mananth(16946)\"\" \"About 
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If Alexandra increases her usual driving speed by 15 km/h, it will take her 2h less to make a trip to her grandparents' house. If she decreases her usual speed by 15 km/h, it will take her 3 h more than usual to make the trip. How long is the trip?\r
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\n" ); document.write( "\n" ); document.write( "let usual speed = x mph
\n" ); document.write( "speed increased by 15km/h
\n" ); document.write( "speed = x+15 km/h
\n" ); document.write( "...
\n" ); document.write( "usual time = y
\n" ); document.write( "time with increased speed = y-2\r
\n" ); document.write( "\n" ); document.write( "xy = (x+15)(y-2)
\n" ); document.write( "xy=xy-2x+15y-30
\n" ); document.write( "2x-15y=-30.....................1\r
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "speed decreased by 15 km/h
\n" ); document.write( "time = y+3
\n" ); document.write( "..
\n" ); document.write( "xy = (x-15)(y+3)
\n" ); document.write( "xy=xy+3x-15y-45
\n" ); document.write( "3x+15y=-45....................2\r
\n" ); document.write( "\n" ); document.write( "2x-15y=-30.....................1\r
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "speed decreased by 15 km/h
\n" ); document.write( "time = y+3
\n" ); document.write( "..
\n" ); document.write( "xy = (x-15)(y+3)
\n" ); document.write( "xy=xy+3x-15y-45
\n" ); document.write( "3x+15y=-45....................2\r
\n" ); document.write( "\n" ); document.write( "2x-15y=-30.............1
\n" ); document.write( "-3x+15y =-45 .............2
\n" ); document.write( "
\n" ); document.write( "multiply (1)by 1
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "2x-15y =-30
\n" ); document.write( "-3x+15y =-45
\n" ); document.write( "
\n" ); document.write( "Add the two equations
\n" ); document.write( "-1x=-75
\n" ); document.write( "/-1
\n" ); document.write( "x=75 km/h
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) 2x-15y =-30
\n" ); document.write( "150-15y =-30
\n" ); document.write( "-15y =-30+-150
\n" ); document.write( "-15y=-180
\n" ); document.write( "y=12 hours\r
\n" ); document.write( "\n" ); document.write( "Distance = speed * time
\n" ); document.write( "Distance = 75*12= 900 km
\n" ); document.write( "
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