document.write( "Question 415096: Mr. Jones invests a total of $23,000 in two accounts paying 7% and 3% annual interest. How much was invested in each account if, after one year, the total interest was $1,410.00? \n" ); document.write( "
Algebra.Com's Answer #291062 by mananth(16946)\"\" \"About 
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7.00% per annum------------- x
\n" ); document.write( "3.00% per annum ------------ y
\n" ); document.write( "total investment 23000
\n" ); document.write( "Interest----- $1,410.00 \r
\n" ); document.write( "\n" ); document.write( "x+y=23000------------------------1
\n" ); document.write( "7.00%x +3.00%y =$1,410.00-------------2
\n" ); document.write( "Multiply by 100
\n" ); document.write( "7x+3y=$141,000.00 --------2
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\n" ); document.write( "Multiply (1) by -7
\n" ); document.write( "we get
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\n" ); document.write( "-7x-7y= -161000
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "-4y=-$20,000.00
\n" ); document.write( "
\n" ); document.write( "divide by -4
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\n" ); document.write( "y=$5,000.00 investment at 3.00%
\n" ); document.write( "Balance $18,000.00 investment at 7.00%
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