document.write( "Question 415109: how do i solve for finding the equation for the line that passes through 0,5 that is perpendicular to the line with the equation 8x+4y=8? \n" ); document.write( "
Algebra.Com's Answer #291060 by mananth(16946)\"\" \"About 
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how do i solve for finding the equation for the line that passes through 0,5 that is perpendicular to the line with the equation 8x+4y=8?\r
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\n" ); document.write( "\n" ); document.write( " 0,5 that is perpendicular to the line with the equation
\n" ); document.write( " 8x+4y=8
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\n" ); document.write( "2x+y=2
\n" ); document.write( "y=-2x+2
\n" ); document.write( "m= slope = -2
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\n" ); document.write( "The perpendicular line will have a slope which is negative reciprocal of the slope of the given line.
\n" ); document.write( "Since m1*m2=-1
\n" ); document.write( "so slope of the required line will be 1/2
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\n" ); document.write( "line passes through (0,5)
\n" ); document.write( "plug the value of slope , and the point to find b the y intercept
\n" ); document.write( "5=(1/2)*0+b
\n" ); document.write( "b=5
\n" ); document.write( "Equation = y=(1/2)x+5
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