document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44161>Question 44161</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve. Approximate irrational roots to the nearest tenth.\r<BR>\n" );
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document.write( "The volume V of a pyramid varies jointly as its altitude H and the area of its base. A pyramid with a nine-inch square base (a square base 9 inches on each side) and an altitude of 10 inches has a volume equal to 270 in^3. Find the volume of a pyramid with an altitude of 6 inches and a square base 4 inches on each side. (units optional) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29106 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29106\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The joint relationship can be expressed as<BR>\n" );
document.write( "V = kbh  (here b = s^2)<BR>\n" );
document.write( "now plug in what we know to find k...<BR>\n" );
document.write( "270 = k(81)(10) so that<BR>\n" );
document.write( "k = 1/3<BR>\n" );
document.write( "Now rewrite using the new k and the data to find the new volume...<BR>\n" );
document.write( "V = (1/3)bh<BR>\n" );
document.write( "V = (1/3)(16)(6)<BR>\n" );
document.write( "V = 32 in^3 </SPAN>\n" );
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