document.write( "Question 415112: how many gallons of a 70% antifreeze solution must be mixed with 100 gallons of 30% antifreeze to get a mixture that is 60% antifreeze? \n" ); document.write( "

Algebra.Com's Answer #291056 by Tatiana_Stebko(1539) $\"\"$ $\"About$

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Let x gallons of 70% antifreeze mix with 100 gallons of 30% antifreeze we'll get (100+x) gallons of new solution
\n" ); document.write( "in 100 gallons of 30% antifreeze is $\"0.3%2A100=30\"$ gallons of antifreeze
\n" ); document.write( "in x gallons of 70% antifreeze is 0.7x gallons
\n" ); document.write( "in (100+x) gallons of 60% antifreeze is 0.6(100+x) gallons
\n" ); document.write( "Equation
\n" ); document.write( " $\"30%2B0.7x=0.6%2A%28100%2Bx%29\"$
\n" ); document.write( " $\"30%2B0.7x=60%2B0.6x\"$
\n" ); document.write( " $\"0.1x=30\"$
\n" ); document.write( " $\"x=30%2F0.1\"$
\n" ); document.write( " $\"x=300\"$ gallons of a 70% antifreeze solution must be mixed with 100 gallons of 30% antifreeze to get a mixture that is 60% antifreeze
\n" ); document.write( "Answer 300 gallons \n" ); document.write( "

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