document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=415060>Question 415060</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the difference between twice a number and three is equal to six decreased by the number..find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #291046 by </B><A HREF=/tutors/aboutme.mpl?userid=se2madon><B>se2madon(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=se2madon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=291046\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi, \r<BR>\n" );
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document.write( "let the number be x<BR>\n" );
document.write( "according to the problem<BR>\n" );
document.write( "twice the number -3= 6- number<BR>\n" );
document.write( "2x-3=6-x<BR>\n" );
document.write( "take the x x value one side & numbers values one side than<BR>\n" );
document.write( "2x+x=-6+3<BR>\n" );
document.write( "3x=9<BR>\n" );
document.write( "x=9/3 (divide 9 by 3)<BR>\n" );
document.write( "x=3;   answer    posted by Dinesh Dongre<BR>\n" );
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