document.write( "Question 415066: patrick drove 5 hours to attend a meeting. on the return trip, his speed was 10 miles per hour less and took 6 hours. what was his speed each way? how far did he drive to the meeting? \n" ); document.write( "
Algebra.Com's Answer #291042 by mananth(16946)\"\" \"About 
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patrick drove 5 hours to attend a meeting. on the return trip, his speed was 10 miles per hour less and took 6 hours. what was his speed each way? how far did he drive to the meeting?
\n" ); document.write( "Going out speed xmph
\n" ); document.write( "returning speed =10mph slower
\n" ); document.write( "returning speed x-10
\n" ); document.write( "returning time = 6 hours
\n" ); document.write( "going out time= 5hours
\n" ); document.write( "
\n" ); document.write( "Distance = same \r
\n" ); document.write( "\n" ); document.write( "5x=6(x-10)
\n" ); document.write( "5x=6x-60
\n" ); document.write( "5x-6x=-60
\n" ); document.write( "-1x=-60
\n" ); document.write( "/-1
\n" ); document.write( "x=60mph
\n" ); document.write( "
\n" ); document.write( "Returning speed= 50 mph
\n" ); document.write( "
\n" ); document.write( "
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