document.write( "Question 415066: patrick drove 5 hours to attend a meeting. on the return trip, his speed was 10 miles per hour less and took 6 hours. what was his speed each way? how far did he drive to the meeting? \n" ); document.write( "
Algebra.Com's Answer #291042 by mananth(16946)![]() ![]() You can put this solution on YOUR website! patrick drove 5 hours to attend a meeting. on the return trip, his speed was 10 miles per hour less and took 6 hours. what was his speed each way? how far did he drive to the meeting? \n" ); document.write( "Going out speed xmph \n" ); document.write( "returning speed =10mph slower \n" ); document.write( "returning speed x-10 \n" ); document.write( "returning time = 6 hours \n" ); document.write( "going out time= 5hours \n" ); document.write( " \n" ); document.write( "Distance = same \r \n" ); document.write( "\n" ); document.write( "5x=6(x-10) \n" ); document.write( "5x=6x-60 \n" ); document.write( "5x-6x=-60 \n" ); document.write( "-1x=-60 \n" ); document.write( "/-1 \n" ); document.write( "x=60mph \n" ); document.write( " \n" ); document.write( "Returning speed= 50 mph \n" ); document.write( " \n" ); document.write( " |