document.write( "Question 415003: Please help me with my last problem::\r
\n" ); document.write( "\n" ); document.write( "On cloudy days, the sun intensity I (in calories per square centimeter) is given by I = I(max) sin‚‚^2 (pi t / D) where I(max) is the largest sun intensity and D is the number of daylight hours. If D = 12, how many hours after sunrise is intensity exactly half of the maximum level? (Assume t is in between zero and D) \r
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Algebra.Com's Answer #290989 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
On cloudy days, the sun intensity I (in calories per square centimeter) is given by I = I(max) sin^2 (pi t / D) where I(max) is the largest sun intensity and D is the number of daylight hours. If D = 12, how many hours after sunrise is intensity exactly half of the maximum level? (Assume t is in between zero and D)
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\n" ); document.write( "Solve sin^2[(pi/12)t] = 1/2
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\n" ); document.write( "sin[(pi/12)t] = sqrt(2)/2
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\n" ); document.write( "(pi/12)t = pi/4
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\n" ); document.write( "(t/12) = 1/4
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\n" ); document.write( "t = 3 hrs.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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