document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=414992>Question 414992</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose you want to combine two types of fruit drink to creat 24 kkilograms of a drink that will be 5% sugar by weight. fruit drink A is 4% sugar by weight, and fruit drink B is 8% sugar by weight </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #290987 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=290987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> suppose you want to combine two types of fruit drink to creat 24 kilograms of a drink that will be 5% sugar by weight. fruit drink A is 4% sugar by weight, and fruit drink B is 8% sugar by weight<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "sugar + sugar = sugar<BR>\n" );
document.write( "0.04x + 0.08(24-x) = 0.05*24<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "4x + 8*24 - 8x = 5*24<BR>\n" );
document.write( "-4x = -3*24<BR>\n" );
document.write( "x = 18 kg (amt. of 4% drink)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "24-x = 6 kg (amt. of 8% drink)<BR>\n" );
document.write( "=================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==========<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );