document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=414921>Question 414921</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary and one is 40 degrees more than three times the other. find the smaller angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #290962 by </B><A HREF=/tutors/aboutme.mpl?userid=praseenakos@yahoo.com><B>praseenakos@yahoo.com(507)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=praseenakos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=praseenakos@yahoo.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=290962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> supplementary angles add up to 180 degrees<BR>\n" );
document.write( " let the smaller angle be  x degrees<BR>\n" );
document.write( "then the other is  3x + 40 degrees<BR>\n" );
document.write( "their sum should be 180 degrees\r<BR>\n" );
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document.write( "so  x + 3x + 40 = 180\r<BR>\n" );
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document.write( "==>  4x + 40  = 180\r<BR>\n" );
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document.write( "==>   4x = 180 - 40\r<BR>\n" );
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document.write( "==>  4x = 140 degrees\r<BR>\n" );
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document.write( "==>  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x%2F4++=+140%2F4+ ALIGN=MIDDLE  ALT=\"4x%2F4++=+140%2F4+\"   DISABLED_style= \"max-width:90%; height:auto;\" > degrees\r<BR>\n" );
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document.write( "==>   x = 45 degrees\r<BR>\n" );
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document.write( "smaller angle is 45 degrees </SPAN>\n" );
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