document.write( "Question 414895: I am having trouble with a quadratic word problem. The word problem is as follows:
\n" ); document.write( "The sides of one square have length 3 m more than the sides of a second square. If the area of the larger square is subtracted from 4 times the area of the smaller square, the result is 36 m^2. What are the lengths of the sides of each square?
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Algebra.Com's Answer #290945 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The sides of one square have length 3 m more than the sides of a second square. If the area of the larger square is subtracted from 4 times the area of the smaller square, the result is 36 m^2. What are the lengths of the sides of each square?\r
\n" ); document.write( "\n" ); document.write( "----
\n" ); document.write( "1st Square DATA:
\n" ); document.write( "Side = x
\n" ); document.write( "Area = x^2
\n" ); document.write( "---
\n" ); document.write( "2nd Square DATA:
\n" ); document.write( "side = x+3
\n" ); document.write( "Area = (x+3)^2
\n" ); document.write( "------
\n" ); document.write( "Equation:
\n" ); document.write( " 4*smaller area - larger area = 36 m^2
\n" ); document.write( "4x^2 - (x+3)^2 = 36
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\n" ); document.write( "4x^2-[x^2+6x+9] - 36 = 0
\n" ); document.write( "---
\n" ); document.write( "4x^-x^2-6x-9-36 = 0
\n" ); document.write( "3x^2-6x-45 = 0
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\n" ); document.write( "x^2-2x-15 = 0
\n" ); document.write( "(x-7)(x+2) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 7m (side of smaller square)
\n" ); document.write( "x+3 = 10m (side of larger square)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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