document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=414817>Question 414817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many liters of a 3%saline solution must be added to an 8% saline solution to obtain 20 liters of a 6% saline solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #290925 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=290925\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many liters of a 3%saline solution must be added to an 8% saline solution to obtain 20 liters of a 6% saline solution<BR>\n" );
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document.write( "Let x = amount (liters) of 3% solution<BR>\n" );
document.write( "then<BR>\n" );
document.write( "20-x = amount (liters) of 8% solution<BR>\n" );
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document.write( ".03x + .08(20-x) = .06(20)<BR>\n" );
document.write( ".03x + 1.6 - .08x = 1.2<BR>\n" );
document.write( "1.6 - .05x = 1.2<BR>\n" );
document.write( "-.05x = -0.4<BR>\n" );
document.write( "x = 8 liters (3% solution)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Amount of 8% solution:<BR>\n" );
document.write( "20-x = 20-8 = 12 liters<BR>\n" );
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