document.write( "Question 414745: The square of the sum of two consecutive integers is 81, find the two integers.
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Algebra.Com's Answer #290901 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Let x and (x+1) represent the two consecutive integers
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document.write( "Question states***
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document.write( " [x + (x+1)]^2 = 81
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document.write( "Solving for x
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document.write( " (2x+1)^2 = 81
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document.write( " 4x^2 + 4x + 1 = 81
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document.write( " 4x^2 + 4x -80 = 0
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document.write( " x^2 + x -20 = 0
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document.write( "factoring
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document.write( "(x+5)(x-4) = 0
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document.write( "(x+5)= 0   x = -5    the two consecutive integers are -5,-4
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document.write( "or
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document.write( "(x-4) = 0  x = 4     the two consecutive integers are 4,5
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document.write( "CHECKING our Answer***
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document.write( " (-9)^2 = 81
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document.write( " (9)^2= 81 \n" );
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