document.write( "Question 44158: solve. approximate irrational roots to the nearest tenth.\r
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document.write( "The length of a rectangle is 3 cm greater than its width. The area of the rectangle is 180 cm^2. find the length and width. (units optional) \n" );
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Algebra.Com's Answer #29090 by adamchapman(301) ![]() You can put this solution on YOUR website! W = width \n" ); document.write( "L = length \n" ); document.write( "A = area = 180 \n" ); document.write( "The length of the rectangle is 2 inches more than twice its width: \n" ); document.write( "L = W + 3..............(i) \r \n" ); document.write( "\n" ); document.write( "A = W x L..............(ii) \n" ); document.write( "Subtitute equation (i) into (ii) for L: \n" ); document.write( "A = W(W + 3) \n" ); document.write( "A = W^2 + 3W \n" ); document.write( "180 = W^2 + 3W \n" ); document.write( "W^2 + 3W -180 = 0\r \n" ); document.write( "\n" ); document.write( "Solve the quadratic equation to give W=-12.75cm or W=14.25cm \n" ); document.write( "Obviously the first solution is impossible, so the true answer is W=14.25cm. Add 3cm to W to get L=17.25cm \n" ); document.write( "I hope this helps \n" ); document.write( "P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk \n" ); document.write( " |