document.write( "Question 414738: The baso of a triangle is x cm longh and its altitude is quarter the length of its base. if the area of the triangle is 12 cm2, form an equation in x and solve it. state the altitude of the triangle. \n" ); document.write( "
Algebra.Com's Answer #290899 by praseenakos@yahoo.com(507)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Area = \"+%281%2F2%29+%2A+base+%2A+altitude+\"\r
\n" ); document.write( "\n" ); document.write( "Given,
\n" ); document.write( " Base = x cm\r
\n" ); document.write( "\n" ); document.write( "Altitude = \"+%281%2F4%29%2A+x+\" cm\r
\n" ); document.write( "\n" ); document.write( "Area = 12 cm2\r
\n" ); document.write( "\n" ); document.write( "==> \"+12+=+%281%2F2%29+%2A+x+%2A%281%2F4%29%2A+x++\"\r
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\n" ); document.write( "\n" ); document.write( "==> \"+12+=+%281%2F8%29+%2A+x%5E2++\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "==> \"+12+%2A+8+=+8%2A%281%2F8%29+%2A+x%5E2++\"\r
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\n" ); document.write( "\n" ); document.write( "==> \"+96+=+x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "==> \"+x+=++sqrt%2896%29\" which is the base\r
\n" ); document.write( "\n" ); document.write( "to get the altitude, divide base by 4\r
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