document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=414679>Question 414679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> During a multi-day camping trip, Terry rowed 17 hours downstream.  It took 26.5 hours rowing upstream to travel the same distance.  If the speed of the current is 6.8 k/h less than his rowing speed in still water, find his rowing speed and the speed of the current.  \r<BR>\n" );
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document.write( "t is time, 26.5 and 17<BR>\n" );
document.write( "r is rate, r, r-6.8\r<BR>\n" );
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document.write( "Distance is the same, so I set the equations equal to each other?  \r<BR>\n" );
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document.write( "17r = 26.5(r-6.8)\r<BR>\n" );
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document.write( "I'm not sure if this is correct, and where I go from here.  \r<BR>\n" );
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document.write( "Please advise.\r<BR>\n" );
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document.write( "Thank you.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #290880 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=290880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> During a multi-day camping trip, Terry rowed 17 hours downstream. It took 26.5 hours rowing upstream to travel the same distance. If the speed of the current is 6.8 k/h less than his rowing speed in still water, find his rowing speed and the speed of the current.<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Downstream DATA:<BR>\n" );
document.write( "time = 17 hrs ; rate = r+(r-6.8) km/h ; distance = t*r = 17(2r-6.8) km<BR>\n" );
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document.write( "Upstream DATA :<BR>\n" );
document.write( "time = 26.5 ; rate = r -(r-6.8) km/h ; distance = t*r = 26.5(6.8) km<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "distance up = distance down<BR>\n" );
document.write( "26.5*6.8 = 17(2r-6.8)<BR>\n" );
document.write( "180.2 = 34r-115.6<BR>\n" );
document.write( "34r = 295.8<BR>\n" );
document.write( "r = 8.7 km/h (rowing speed)<BR>\n" );
document.write( "r-6.8 = 1.9 km/h (speed of the current)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "===============  \r<BR>\n" );
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document.write( " <BR>\n" );
document.write( "t is time, 26.5 and 17<BR>\n" );
document.write( "r is rate, r, r-6.8 <BR>\n" );
document.write( "Distance is the same, so I set the equations equal to each other? <BR>\n" );
document.write( "17r = 26.5(r-6.8) <BR>\n" );
document.write( "I'm not sure if this is correct, and where I go from here </SPAN>\n" );
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