document.write( "Question 44153This question is from textbook Begining Algebra
\n" ); document.write( ": Geometry. The length of a rectangle is 2 inches more than twice its width. If the perimeter of the rectangle is 34 inches, find the demensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #29088 by adamchapman(301)\"\" \"About 
You can put this solution on YOUR website!
L = length
\n" ); document.write( "W = width
\n" ); document.write( "P = perimeter = 34\r
\n" ); document.write( "\n" ); document.write( "The length of the rectangle is 2 inches more than twice its width:
\n" ); document.write( "L = 2W + 2..............(i)\r
\n" ); document.write( "\n" ); document.write( "The perimeter is the sum of all side lengths:
\n" ); document.write( "P = 2W +2L..............(ii)\r
\n" ); document.write( "\n" ); document.write( "Subtitute equation (i) into (ii) for L:
\n" ); document.write( "P = 2W +2(2W + 2)
\n" ); document.write( "P = 2W + 4W + 4
\n" ); document.write( "P = 6W + 4
\n" ); document.write( "P = 34\r
\n" ); document.write( "\n" ); document.write( "6W + 4 = 34
\n" ); document.write( "6W = 30
\n" ); document.write( "W = 5 in.\r
\n" ); document.write( "\n" ); document.write( "Subtitute W=5 into equation (i) for W:
\n" ); document.write( "L = 2(5) + 2
\n" ); document.write( "L = 12 in.\r
\n" ); document.write( "\n" ); document.write( "I hope this helps
\n" ); document.write( "P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk
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