document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=414691>Question 414691</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second of three numbers is 8 more than twice the first. The third number is twelve less than the first. The sum of the number is 108. Find the numbers\r<BR>\n" );
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document.write( "work so far--> 2n+8+n-12=108<BR>\n" );
document.write( "        3n+8-12=108 added the n's <BR>\n" );
document.write( "                3n+8=120 added 12<BR>\n" );
document.write( "                  3n=112 subtracted 8<BR>\n" );
document.write( "                   when I divided 112/3 I get an irrational number and dont know what to do after  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #290872 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=290872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The second of three numbers is 8 more than twice the first. The third number is twelve less than the first. The sum of the number is 108. Find the numbers<BR>\n" );
document.write( "work so far--> 2n+8+n-12=108<-----------------*you forgot to add \"n\" the 1st number*<BR>\n" );
document.write( "3n+8-12=108 added the n's<BR>\n" );
document.write( "3n+8=120 added 12<BR>\n" );
document.write( "3n=112 subtracted 8<BR>\n" );
document.write( "when I divided 112/3 I get an irrational number and dont know what to do after \r<BR>\n" );
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document.write( "n = first number<BR>\n" );
document.write( "2n + 8 = second number {8 more than twice the first}<BR>\n" );
document.write( "n - 12 = third number {12 less than the first}\r<BR>\n" );
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document.write( "n + 2n + 8 + n - 12 = 108 {sum of numbers is 108}<BR>\n" );
document.write( "4n - 4 = 108 {combined like terms}<BR>\n" );
document.write( "4n = 112 {added 4 to both sides}<BR>\n" );
document.write( "n = 28 {divided both sides by 4}<BR>\n" );
document.write( "2n + 8 = 64 {substituted 28, in for n, into 2n + 8}<BR>\n" );
document.write( "n - 12 = 16 {substituted 28, in for n, into n - 12}<BR>\n" );
document.write( "  \r<BR>\n" );
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document.write( "28, 64, and 16 are the three numbers<BR>\n" );
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