document.write( "Question 414384: 3x2-y2
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document.write( "for x=1/2
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document.write( "y=-1/3 \n" );
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Algebra.Com's Answer #290811 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! I'm guessing that the 2's are exponents. If this is correct, please use the \"^\" character to indicate exponents: \n" ); document.write( "3x^2-y^2 \n" ); document.write( "I'm also guessing the problem is to evaluate the expression when x = 1/2 and y = 1/3. To do this we just substitute the values for x and y and use the order of operations (aka PEMDAS) to simplify: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Note the use of parentheses. This is a good habit whenever you are substituting one expression for another. \n" ); document.write( "Next, according to the order of operations we should exponentiate: \n" ); document.write( " \n" ); document.write( "Next, multiply: \n" ); document.write( " \n" ); document.write( "and last, subtract. Since these are fractions we need common denominators: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |