document.write( "Question 414384: 3x2-y2
\n" ); document.write( "for x=1/2
\n" ); document.write( "y=-1/3
\n" ); document.write( "

Algebra.Com's Answer #290811 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
I'm guessing that the 2's are exponents. If this is correct, please use the \"^\" character to indicate exponents:
\n" ); document.write( "3x^2-y^2

\n" ); document.write( "I'm also guessing the problem is to evaluate the expression when x = 1/2 and y = 1/3. To do this we just substitute the values for x and y and use the order of operations (aka PEMDAS) to simplify:
\n" ); document.write( "\"3x%5E2-y%5E2\"
\n" ); document.write( "\"3%281%2F2%29%5E2-%281%2F3%29%5E2\"
\n" ); document.write( "Note the use of parentheses. This is a good habit whenever you are substituting one expression for another.
\n" ); document.write( "Next, according to the order of operations we should exponentiate:
\n" ); document.write( "\"3%281%2F4%29-%281%2F9%29\"
\n" ); document.write( "Next, multiply:
\n" ); document.write( "\"3%2F4-1%2F9\"
\n" ); document.write( "and last, subtract. Since these are fractions we need common denominators:
\n" ); document.write( "\"%283%2F4%29%289%2F9%29-%281%2F9%29%284%2F4%29\"
\n" ); document.write( "\"27%2F36-4%2F36\"
\n" ); document.write( "\"23%2F36\"
\n" ); document.write( "
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