document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44145>Question 44145</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072549017/algebrahomeworkh>Begining Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Business and finance. A coffee merchant has coffe beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100 pounds of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29081 by </B><A HREF=/tutors/aboutme.mpl?userid=adamchapman><B>adamchapman(301)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=adamchapman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "A = proportion of coffee beans that sell for $9 per pound <BR>\n" );
document.write( "B = proportion of coffee beans that sell for $12 per pound\r<BR>\n" );
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document.write( "A and B are percentages written in decimal form (e.g. 50%=0.5), and make the whole mix:<BR>\n" );
document.write( "A+B=1 ..........................i\r<BR>\n" );
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document.write( "The price of the mixture is $11.25 per pound:<BR>\n" );
document.write( "A($9)+B($12)=$11.25.............ii\r<BR>\n" );
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document.write( "Rearrange equation (i) to give B in terms of A:<BR>\n" );
document.write( "B=1-A...........................iii\r<BR>\n" );
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document.write( "Substitute equation (iii) into equation (ii) for B:<BR>\n" );
document.write( "A($9)+(1-A)($12)=$11.25.........iv\r<BR>\n" );
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document.write( "12-3A=11.25<BR>\n" );
document.write( "3A=0.75<BR>\n" );
document.write( "A=0.25..........................v<BR>\n" );
document.write( "Substitute equation (v) into equation (iii) for A to give:<BR>\n" );
document.write( "B=0.75\r<BR>\n" );
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document.write( "So quarter of the mixture is made of \"type A\" beans and the remaining three quarters of the mix consists of \"type B\" beans.\r<BR>\n" );
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document.write( "I hope this helps <BR>\n" );
document.write( "P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk \r<BR>\n" );
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document.write( " </SPAN>\n" );
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