document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44145>Question 44145</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072549017/algebrahomeworkh>Begining Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Business and finance. A coffee merchant has coffe beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100 pounds of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29080 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let us suppose that the Merchant mixed 'x' lbs of the $9 beans with 'y' lbs of $12 beans.\r<BR>\n" );
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document.write( "Hence, he created (x+y) lbs of mixture.<BR>\n" );
document.write( "Given, total 100 lbs of the mixture is produced.<BR>\n" );
document.write( "So, x + y = 100 _________(1)\r<BR>\n" );
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document.write( "Therefore, the cost of (x+y) lbs of the mixture = $(9x+12y).<BR>\n" );
document.write( "Hence, the cost of 1 lb of the mixture = $<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%289x%2B12y%29%2F%28x%2By%29 ALIGN=MIDDLE  ALT=\"%289x%2B12y%29%2F%28x%2By%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Given, cost of 1 lb the mixture = $11.25.<BR>\n" );
document.write( "So, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%289x%2B12y%29%2F%28x%2By%29+=+11.25 ALIGN=MIDDLE  ALT=\"%289x%2B12y%29%2F%28x%2By%29+=+11.25\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%289x%2B12y%29=11.25%28x%2By%29 ALIGN=MIDDLE  ALT=\"%289x%2B12y%29=11.25%28x%2By%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12y+-+11.25y+=+11.25x+-+9x ALIGN=MIDDLE  ALT=\"12y+-+11.25y+=+11.25x+-+9x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.75y+=+2.25x ALIGN=MIDDLE  ALT=\"0.75y+=+2.25x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+2.25x%2F0.75 ALIGN=MIDDLE  ALT=\"y+=+2.25x%2F0.75\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or y = 3x ________(2)\r<BR>\n" );
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document.write( "Substituting the value of 'y' from (2) in (1) we have<BR>\n" );
document.write( "x + 3x = 100<BR>\n" );
document.write( "or 4x = 100<BR>\n" );
document.write( "or x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=100%2F4 ALIGN=MIDDLE  ALT=\"100%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or x = 25\r<BR>\n" );
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document.write( "Substituting, x = 25 in (2), y = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2A25 ALIGN=MIDDLE  ALT=\"3%2A25\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 75\r<BR>\n" );
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document.write( "Hence, 25 lbs of the $9 beans is to be mixed with 75 lbs of $12 beans to serve the reqd. purpose. </SPAN>\n" );
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