document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=414444>Question 414444</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At noon a private plane left Austin for Los Angeles, 2100 km away, flying at 500km/hr.  One hour later a jet left Los Angeles for Austin at 700km/hr.  At what time will they meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #290670 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=290670\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At noon a private plane left Austin for Los Angeles, 2100 km away, flying at 500km/hr.  One hour later a jet left Los Angeles for Austin at 700km/hr.  At what time will they meet?<BR>\n" );
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document.write( "In 1 hour, the 1st plane is 500 km away (500 km/hr * 1 hr)<BR>\n" );
document.write( "The 2nd plane gains on the 1st at 200 km/hr (700 - 500)<BR>\n" );
document.write( "500/200 = 2.5 hours<BR>\n" );
document.write( "1300 + 2.5 hours = 1530 (3:30 PM, if you're not an aviator)<BR>\n" );
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document.write( "PS  Planes use knots, not km/hr </SPAN>\n" );
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