document.write( "Question 414440: 5
\n" ); document.write( " divided by
\n" ); document.write( "4 minus the square root of 3
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Algebra.Com's Answer #290667 by stanbon(75887)\"\" \"About 
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5
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\n" ); document.write( "4 minus the square root of 3
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\n" ); document.write( "5/(4-sqrt(3))
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\n" ); document.write( "Multiply numerator and denominator by (4+sqrt(3)) to get:
\n" ); document.write( "= [5(4+sqrt(3)]/[16-3]
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\n" ); document.write( "Note: (4-sqrt(3))(4+sqrt(3)) = 16-(sqrt(3)^2) = 16-3 = 13
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\n" ); document.write( "= [20+5sqrt(3)]/13
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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