document.write( "Question 414362: If the sides of a square are decreased by 2 cm, the area is decreased by
\n" ); document.write( "36 cm2. What were the dimensions of the original square?\r
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\n" ); document.write( "\n" ); document.write( "Please help. I don't even know how to start.
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Algebra.Com's Answer #290646 by Earlsdon(6294)\"\" \"About 
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Let x = the length of the side of the original square and A its area, so...
\n" ); document.write( "\"A+=+x%5E2\" Now decrease the sides by 2 cm (x-2). and the area by 36 (A-36), so now you have:
\n" ); document.write( "\"A-36+=+%28x-2%29%5E2\" Substitute \"A+=+x%5E2\"
\n" ); document.write( "\"x%5E2-36+=+%28x-2%29%5E2\" Simplify.
\n" ); document.write( "\"x%5E2-36+=+x%5E2-4x%2B4\" Combine like-terms.
\n" ); document.write( "\"x%5E2-x%5E2+-36+=+-4x%2B4\"
\n" ); document.write( "\"-36+=+-4x%2B4\" Add 36 to both sides.
\n" ); document.write( "\"0+=+-4x%2B40\" Add 4x to both sides.
\n" ); document.write( "\"4x+=+40\" Divide both sides by 4.
\n" ); document.write( "\"x+=+10\"
\n" ); document.write( "The dimensions of the original square were 10 by 10.
\n" ); document.write( "Check:
\n" ); document.write( "Original area:
\n" ); document.write( "\"A+=+10%5E2\"
\n" ); document.write( "\"A++100\"
\n" ); document.write( "New area:
\n" ); document.write( "\"%2810-2%29%5E2+=+64\"
\n" ); document.write( "Difference in the old and new areas:
\n" ); document.write( "\"100-64+=+36\"
\n" ); document.write( "The new area decreased by 36 sq.cm.
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