document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43813>Question 43813</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534494498/algebrahomeworkh>Algebra and trigonometry with analytic geometry</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The polynomial f(x)divided x-3 results in a quotient of x^2+3x-5 with a remainder of 2.  Find f(3).  my answer is -2,  could that be right.  thanks again. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29064 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the original f(x) we need to multiply<BR>\n" );
document.write( "(x^2 + 3x - 5) by (x - 3) and then adding 2...we get<BR>\n" );
document.write( "f(x) = x^3 - 14x + 15 + 2<BR>\n" );
document.write( "f(x) = x^3 - 14x + 17<BR>\n" );
document.write( "so that <BR>\n" );
document.write( "f(3) = 3^3 - 14(3) + 17<BR>\n" );
document.write( "f(3) = 27 - 42 + 17<BR>\n" );
document.write( "f(3) = 2<BR>\n" );
document.write( "Close, but I get positive 2, not -2. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );