document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=414332>Question 414332</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one root of the quadratic equation x2-kx+8=0 is negative of the other. the value of k is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #290634 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=290634\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> your equation is x^2 - kx + 8 = 0\r<BR>\n" );
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document.write( "unless i completely misunderstand what you are asking for, there is no solution to this equation as far as i can see.\r<BR>\n" );
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document.write( "if one root is the negative of the other root, then you can never get a positive constant value in the equation.\r<BR>\n" );
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document.write( "the only way one root could be the negative of the other is if the roots were equal with opposite signs.\r<BR>\n" );
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document.write( "if the roots were equal, then they would each have to be equal to square root of 8 because the square root of 8 times the square root of 8 equals 8.\r<BR>\n" );
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document.write( "for one of the roots to be a negative of the other, then:\r<BR>\n" );
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document.write( "one of the roots would have to be plus the square root of 8.<BR>\n" );
document.write( "the other root would have to be minus the square root of 8.\r<BR>\n" );
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document.write( "plus the square root of 8 times minus the square root of 8 would result in minus 8.\r<BR>\n" );
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document.write( "but you want them to be equal to plus 8.\r<BR>\n" );
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document.write( "can't be done.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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