document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=414333>Question 414333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x-2y=-31<BR>\n" );
document.write( "5x+-2y=-49\r<BR>\n" );
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document.write( "Solve linear systems by adding or subtracting\r<BR>\n" );
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document.write( "From Holt McDougal text: Florida Larson Algebra 1\r<BR>\n" );
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document.write( "Chapter/Section 7.3 extra practice page 908 problem 15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #290633 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=290633\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x-2y=-31<BR>\n" );
document.write( "5x+-2y=-49 <BR>\n" );
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document.write( "Subtract and solve for \"x\":<BR>\n" );
document.write( "2x = -18<BR>\n" );
document.write( "x = -9<BR>\n" );
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document.write( "Solve for \"y\":<BR>\n" );
document.write( "3x-2y = 31<BR>\n" );
document.write( "3(-9) - 2y = -31<BR>\n" );
document.write( "-27 -2y = -31<BR>\n" );
document.write( "2y = 4<BR>\n" );
document.write( "y = 2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "========== </SPAN>\n" );
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