document.write( "Question 414240: A man is 10 years older than his son. In ten years, he will be twice as old as his son will then be. How old is each \n" ); document.write( "
Algebra.Com's Answer #290623 by Edwin McCravy(20060)\"\" \"About 
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A man is 10 years older than his son.
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document.write( "What??? The man became a father at age 10?????\r\n" );
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document.write( "Surely you miscopied the problem.\r\n" );
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\n" ); document.write( "In ten years, he will be twice as old as his son will then be.
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document.write( "If that were the bizarre case, then\r\n" );
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document.write( "son's age now = x\r\n" );
document.write( "father's age now = x + 10\r\n" );
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document.write( "son's age in 10 years = x + 10\r\n" );
document.write( "father's age in 10 years = (x + 10) + 10 or x + 10 + 10 or x + 20\r\n" );
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document.write( "So \r\n" );
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document.write( "x + 20 = 2(x + 10)\r\n" );
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document.write( "x + 20 = 2x + 20\r\n" );
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document.write( "    -x = 0\r\n" );
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document.write( "     x = 0\r\n" );
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document.write( "son's age now = x = 0\r\n" );
document.write( "father's age now = x + 10 = 0 + 10 = 10\r\n" );
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document.write( "So the 10-year old boy just became a father, for the baby is\r\n" );
document.write( "0 years old (just born).  And in ten years the 10-year-old boy \r\n" );
document.write( "father will be 20 years old and the son will be 10.\r\n" );
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document.write( "That works, but surely the problem is botched.\r\n" );
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document.write( "Edwin
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