document.write( "Question 414299: The frequency or number (f) of vibration of a string under constant tension is inversely proportional to the length (l) of the string. If a string of 48 cm
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document.write( "vibrates 192 cycles per second, find the the constant of proportionality and the number of vibrations per second a string of 32 cm will make. \n" );
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Algebra.Com's Answer #290615 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The frequency or number (f) of vibration of a string under constant tension is inversely proportional to the length (l) of the string. If a string of 48 cm \n" ); document.write( "vibrates 192 cycles per second, find the the constant of proportionality and the number of vibrations per second a string of 32 cm will make. \n" ); document.write( "---- \n" ); document.write( "f = k/L \n" ); document.write( "--- \n" ); document.write( "Find \"k\" using \"a string of 48 cm \n" ); document.write( "vibrates 192 cycles per second\". \n" ); document.write( "--- \n" ); document.write( "192 = k/48 \n" ); document.write( "k = 9216 (constant of proportionality) \n" ); document.write( "--- \n" ); document.write( "Equation: \n" ); document.write( "Find \"the number of vibrations per second a string of 32 cm will make\" \n" ); document.write( "using y = 9216/L \n" ); document.write( "y = 9216/32 = 288 vibrations per second \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " \n" ); document.write( " |