document.write( "Question 414318: Hello! I am having a lot of trouble with logs. I understand the rules for the most part. \r
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Algebra.Com's Answer #290602 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
log3x = .24863
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document.write( "You need the rule for changing a log equation to an\r\n" );
document.write( "exponential equation and vice-versa:\r\n" );
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document.write( "That rule is this:\r\n" );
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document.write( "The logarithm equation:\r\n" );
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document.write( "logBA = C \r\n" );
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document.write( "is equivalent to the exponential equation:\r\n" );
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document.write( "A = BC\r\n" );
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document.write( "So your logarithm equation \r\n" );
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document.write( "log3x = .24863 is equivalent to\r\n" );
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document.write( "x = 3.24863\r\n" );
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document.write( "And you can do that with a calculator and get\r\n" );
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document.write( "x = 1.314094681\r\n" );
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document.write( "Then take the square root of that and get\r\n" );
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document.write( "Öx = 1.146339688\r\n" );
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document.write( "Edwin

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